Selling trailer rig question

[krisztian1981 14]

Hello all,

I have a big dilemma my fellow cleaners. I want to sell my rig, i'm just not sure how i should list it. here are the specs and let me know what you guys think....

20HP Honda 3000Psi at 8GPM

1 225gal water tank

1 135gal chemical tank

1 55gal chemical tank

75' water hose with reel

300' high pressure hose with a reel

300' chemical hose with reel

1 flojet 3.7gpm pump

6'x12' tandem trailer

and now here is my dilemma....

I also have a HOT WATER DIESEL BURNER, but i took it off. should i put it back on and try to sell it with the burner or without?

how much do you think i can ask for it? the rig is about 1.5 years old it runs like new i changed the oil on it weekly.

Thanx for all your suggestions

[Kory 14]

I think it would be hard to get 3k psi and 8 gpm out of a 20hp honda

[One Tough Pressure 580]

Pressure Pro does an 8 at 3000 skid, and I have done it before as well. It works the engine hard, but it can be done.

Might as well include the burner, unless you have another use for it.

[PWkid 79]

3000psi x 8gpm = 24000 / 1100= 21.8 hp

[big pressure 14]

I have my udor 8 gpm on a 21 hp briggs.....it turns and burns....hey is that hot box rated for 8 gpm

[dcoronado 19]

3000psi x 8gpm = 24000 / 1100= 21.8 hp

Mel,

Educate me. Why do you divide the 24000 by 1100?

[krisztian1981 14]

yes it is, its from pressure pro

[chris francis 15]

I am little lost is hot box that you took off or is just burner that you took off.

[Paul Kassander 26]

1100 is the factor used for gasoline engines to determine the hp requirements. This is an excerpt from our technical library to help.

Power Plants, Power Requirement Formulas

Pressure washers are generally powered by gasoline engines, diesel engines, propane fired engines, or electric motors. Force created by the power plant turns the pressure pump, which in turn moves the water. A power plant must have enough force to continue to turn the pump crankshaft when the pump is pushing water out its rated flow and pressure. The following formulas are used to determine how much power is required to drive a specific pump. The power is measured in horsepower. GPM x PSI then divide by 1457 Equals EBHP (Electric Motor) GPM x PSI then divide by 1100 Equals Gasoline HP (Industrial) GPM x PSI then divide by 900 Equals Gasoline HP (Standard) GPM x PSI then divide by 1260 Equals Diesel HP Other useful formulas: HP x Constant then divided by GPM = PSI HP x Constant then divided by PSI = GPM

[PWkid 79]

Thanks Paul for bailing me out.lol I am not sure the technical reason for dividing by 1100. When I was selling equipment I learned the formula for gas and electric motor HP requirements.

[CCPC 26]

do you have any pictures of the rig/equipment?